the-sum-of-all-x-values-x-2-6x-9-x-3-x-1-x-3-x-4-

Question Number 110471 by abdullahquwatan last updated on 29/Aug/20

the sum of all x values

{(x^{2} - 6 x + 9)}^{\frac{x - 3}{x - 1}} = {(x - 3)}^{(x - 4)}

Answered by Rasheed.Sindhi last updated on 29/Aug/20

{(x^{2} - 6 x + 9)}^{\frac{x - 3}{x - 1}} = {(x - 3)}^{(x - 4)}

{({(x - 3)}^{2})}^{\frac{x - 3}{x - 1}} = {(x - 3)}^{(x - 4)}

^{∙} \frac{2 (x - 3)}{x - 1} = x - 4

2 x - 6 = x^{2} - 5 x + 4

x^{2} - 7 x + 10 = 0

(x - 2) (x - 5) = 0

x = 2 \lor x = 5

^{∙} x - 3 = 0, 1 \Rightarrow x = 3 \lor x = 4

B u t x = 3 p r o d u c e s i n d e t e r m i n a t e

f o r m 0^{0}

S o S o l u t i o n S e t i s

{2, 4, 5}

Commented by abdullahquwatan last updated on 29/Aug/20

3 included ?

Commented by Rasheed.Sindhi last updated on 29/Aug/20

S o r r y {i t}^{'} s e x c l u d e d b e c a u s e x = 3

g i v e s i n d e t e r m i n a t e f o r m 0^{0}

Commented by Rasheed.Sindhi last updated on 29/Aug/20

T h a n k s a b d u l l a h f o r

m e n t k o n i n g e r r o r .

Commented by abdullahquwatan last updated on 29/Aug/20

thank you sir