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The-sum-of-the-digits-in-the-unit-place-of-all-four-digit-numbers-formed-using-the-numbers-3-4-5-andL-6-without-repetition-is-a-432-b-108-c-36-d-18-




Question Number 52379 by Necxx last updated on 07/Jan/19
The sum of the digits in the unit  place of all four digit numbers  formed using the numbers 3 4 5 andL  6 without repetition is  a)432 b)108 c)36 d)18
Thesumofthedigitsintheunitplaceofallfourdigitnumbersformedusingthenumbers345andL6withoutrepetitionisa)432b)108c)36d)18
Answered by tanmay.chaudhury50@gmail.com last updated on 07/Jan/19
4our digit numbers=4!=24  while adding we have to add each digit(3,4,5,6)  6 times  so sum of digut in unit place is  6(3+4+5+6)=108
4ourdigitnumbers=4!=24whileaddingwehavetoaddeachdigit(3,4,5,6)6timessosumofdigutinunitplaceis6(3+4+5+6)=108
Commented by Necxx last updated on 07/Jan/19
sorry for my funny questions but  why did you multiply by 6 times.  When I solved I had 18 by just  adding all the digits but your  answer is the correct one.Thanks  in advance.
sorryformyfunnyquestionsbutwhydidyoumultiplyby6times.WhenIsolvedIhad18byjustaddingallthedigitsbutyouransweristhecorrectone.Thanksinadvance.
Commented by mr W last updated on 07/Jan/19
there are 3!=6 numbers whose last  digit is 3, 4, 5, 6 respectively.
thereare3!=6numberswhoselastdigitis3,4,5,6respectively.
Commented by tanmay.chaudhury50@gmail.com last updated on 08/Jan/19
− − − −^3  unit place 3→(3×2×1)=6nos  − − − −^4  unit place 4→(3×2×1)=6 nos  − − − −^5  unit place 5 →(3×2×1)=6nos   − − − −^6  unit place 6 →(3×2×1)=6 nos  now add them....you have to add=6(3+4+5+6)=108..
3unitplace3(3×2×1)=6nos4unitplace4(3×2×1)=6nos5unitplace5(3×2×1)=6nos6unitplace6(3×2×1)=6nosnowaddthem.youhavetoadd=6(3+4+5+6)=108..

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