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The-tangent-to-the-curve-y-x-3-bx-where-b-is-constant-at-x-1-passes-through-the-points-A-1-6-and-2-15-Find-the-value-of-b-




Question Number 56738 by pieroo last updated on 22/Mar/19
The tangent to the curve y=x^3 +bx, where  b is constant, at x=1 passes through the  points A(−1,6) and (2,−15). Find the  value of b.
Thetangenttothecurvey=x3+bx,wherebisconstant,atx=1passesthroughthepointsA(1,6)and(2,15).Findthevalueofb.
Answered by tanmay.chaudhury50@gmail.com last updated on 22/Mar/19
(dy/dx)=3x^2 +b→m=3+b  eqn y=(3+b)x+c  6=(3+b)×−1+c  −15=(3+b)×2+c  21=(3+b)(−1−2)  3+b=−7  b=−10
dydx=3x2+bm=3+beqny=(3+b)x+c6=(3+b)×1+c15=(3+b)×2+c21=(3+b)(12)3+b=7b=10
Commented by pieroo last updated on 22/Mar/19
Thanks boss
Thanksboss
Commented by tanmay.chaudhury50@gmail.com last updated on 22/Mar/19
most welcome
mostwelcome

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