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Question Number 33413 by Rio Mike last updated on 15/Apr/18
  the value of θ,in the range 0° ≤  θ≤90°  for which sinθ = cos θ is...?
thevalueofθ,intherange0°θ90°forwhichsinθ=cosθis?
Commented by Rasheed.Sindhi last updated on 16/Apr/18
sinθ=cos(90−θ)     θ=90−θ     2θ=90      θ=45  sin45=cos45
sinθ=cos(90θ)θ=90θ2θ=90θ=45sin45=cos45
Commented by abdo imad last updated on 17/Apr/18
sinθ =cosθ ⇔ sinθ =sin((π/2)−θ) ⇔ θ =(π/2) −θ +2kπ or  θ =π −((π/2)−θ) +2kπ (k∈Z) ⇔ 2θ  = (π/2) +2kπ or θ=(π/2) +θ +2kπ  ⇔ θ =(π/4) +kπ  but we have 0≤θ≤(π/2) ⇒ 0≤(π/4) +kπ≤(π/2)  ⇒0 ≤(1/4) +k ≤(1/2) ⇒−(1/4) ≤k ≤ (1/4) ⇒k=0 ⇒θ =(π/4) .
sinθ=cosθsinθ=sin(π2θ)θ=π2θ+2kπorθ=π(π2θ)+2kπ(kZ)2θ=π2+2kπorθ=π2+θ+2kπθ=π4+kπbutwehave0θπ20π4+kππ2014+k1214k14k=0θ=π4.

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