The-velocity-of-a-ship-Q-relqtive-to-a-ship-P-is-10km-h-in-a-direction-N45-E-If-the-velocity-of-P-is-20km-h-in-a-direction-N60-W-Find-the-actual-velocity-of-Q-in-magnitude-and-direction-

Question Number 47194 by Necxx last updated on 06/Nov/18

T h e v e l o c i t y o f a s h i p Q r e l q t i v e t o

a s h i p P i s 10 k m / h i n a d i r e c t i o n

N 45^{.} E . I f t h e v e l o c i t y o f P i s 20 k m / h

i n a d i r e c t i o n N 60^{.} W . F i n d t h e

a c t u a l v e l o c i t y o f Q i n m a g n i t u d e

a n d d i r e c t i o n .

Commented by Necxx last updated on 06/Nov/18

p l e a s e h e l p

Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

p i c t u r e f o r c l a r i t y o f d i r e c t i o n \dots

Answered by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

{\vec{V}}_{p} = - 20 s i n 60^{o} i + 20 c o s 60^{o} j

v e l o c i t y o f Q r e l a t i v e t o P i s

{\vec{V}}_{Q} - {\vec{V}}_{P} = 10 s i n 45^{o} i + 10 c o s 45^{o} j

{\vec{V}}_{Q} = i (10 \times \frac{1}{\sqrt{2}} - 20 \times \frac{\sqrt{3}}{2}) + j (10 \times \frac{1}{\sqrt{2}} + 20 \times \frac{1}{2})

{\vec{V}}_{Q} = i (5 \times 1.41 - 10 \times 1.732) + j (5 \times 1.41 + 10)

= i (7.05 - 17.32) + j (7.05 + 10)

= i (- 10.27) + j (17.5)

p l s c h e c k \dots

Commented by Necxx last updated on 06/Nov/18

y e a h \dots . i c q l c u l a t e d t h e m o d u l u s

a n d d i r e c t i o n o f t h e v a l u e . i t s r e a l l y

c o r r e c t . T h a n k s

Commented by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18

t h a n k s \dots