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The-x-n-sequence-is-specified-by-the-conditions-x-1-1982-x-n-1-1-4-x-n-n-0-find-lim-n-x-n-




Question Number 154252 by EDWIN88 last updated on 16/Sep/21
  The {x_n } sequence is specified   by the conditions      { ((x_1 =1982)),((x_(n+1) =(1/(4−x_n )),n≥0)) :}   find lim_(n→∞) x_n .
$$\:\:{The}\:\left\{{x}_{{n}} \right\}\:{sequence}\:{is}\:{specified} \\ $$$$\:{by}\:{the}\:{conditions}\: \\ $$$$\:\:\begin{cases}{{x}_{\mathrm{1}} =\mathrm{1982}}\\{{x}_{{n}+\mathrm{1}} =\frac{\mathrm{1}}{\mathrm{4}−{x}_{{n}} },{n}\geqslant\mathrm{0}}\end{cases} \\ $$$$\:{find}\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}{x}_{{n}} . \\ $$

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