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Question Number 58253 by pete last updated on 20/Apr/19
There are 100, 150 and 250 students in  forms one, two and three, respectively  in a school. If the mean ages of tbe students in  the forms are 15.6 years, 16.8 years and  18years respectively, find  i. the total number of students in the forms  ii. correct to one decimal place, the mean  age of all the students
$$\mathrm{There}\:\mathrm{are}\:\mathrm{100},\:\mathrm{150}\:\mathrm{and}\:\mathrm{250}\:\mathrm{students}\:\mathrm{in} \\ $$$$\mathrm{forms}\:\mathrm{one},\:\mathrm{two}\:\mathrm{and}\:\mathrm{three},\:\mathrm{respectively} \\ $$$$\mathrm{in}\:\mathrm{a}\:\mathrm{school}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{ages}\:\mathrm{of}\:\mathrm{tbe}\:\mathrm{students}\:\mathrm{in} \\ $$$$\mathrm{the}\:\mathrm{forms}\:\mathrm{are}\:\mathrm{15}.\mathrm{6}\:\mathrm{years},\:\mathrm{16}.\mathrm{8}\:\mathrm{years}\:\mathrm{and} \\ $$$$\mathrm{18years}\:\mathrm{respectively},\:\mathrm{find} \\ $$$$\mathrm{i}.\:\mathrm{the}\:\mathrm{total}\:\mathrm{number}\:\mathrm{of}\:\mathrm{students}\:\mathrm{in}\:\mathrm{the}\:\mathrm{forms} \\ $$$$\mathrm{ii}.\:\mathrm{correct}\:\mathrm{to}\:\mathrm{one}\:\mathrm{decimal}\:\mathrm{place},\:\mathrm{the}\:\mathrm{mean} \\ $$$$\mathrm{age}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{students} \\ $$
Answered by tanmay last updated on 20/Apr/19
N=n_1 +n_2 +n_3 =100+150+250=500  mean=x^− =((n_1 x_1 +n_2 x_2 +n_3 x_3 )/(n_1 +n_2 +n_3 ))  x^− =((100×15.6+150×16.8+250×18)/(500))  =((1560+2520+4500)/(500))  =((8580)/(500))=17.16
$${N}={n}_{\mathrm{1}} +{n}_{\mathrm{2}} +{n}_{\mathrm{3}} =\mathrm{100}+\mathrm{150}+\mathrm{250}=\mathrm{500} \\ $$$${mean}=\overset{−} {{x}}=\frac{{n}_{\mathrm{1}} {x}_{\mathrm{1}} +{n}_{\mathrm{2}} {x}_{\mathrm{2}} +{n}_{\mathrm{3}} {x}_{\mathrm{3}} }{{n}_{\mathrm{1}} +{n}_{\mathrm{2}} +{n}_{\mathrm{3}} } \\ $$$$\overset{−} {{x}}=\frac{\mathrm{100}×\mathrm{15}.\mathrm{6}+\mathrm{150}×\mathrm{16}.\mathrm{8}+\mathrm{250}×\mathrm{18}}{\mathrm{500}} \\ $$$$=\frac{\mathrm{1560}+\mathrm{2520}+\mathrm{4500}}{\mathrm{500}} \\ $$$$=\frac{\mathrm{8580}}{\mathrm{500}}=\mathrm{17}.\mathrm{16} \\ $$
Commented by pete last updated on 20/Apr/19
thanks sir
$$\mathrm{thanks}\:\mathrm{sir} \\ $$
Commented by tanmay last updated on 20/Apr/19
most welcome..
$${most}\:{welcome}.. \\ $$

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