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There-are-two-crystalline-forms-of-PbO-one-is-yellow-and-the-other-is-red-The-standard-enthalpies-of-formation-of-these-two-forms-are-217-3-and-219-kJ-per-mole-respectively-Calculate-the-enthalp




Question Number 18846 by Tinkutara last updated on 30/Jul/17
There are two crystalline forms of PbO ;  one is yellow and the other is red. The  standard enthalpies of formation of  these two forms are −217.3 and −219  kJ per mole respectively. Calculate the  enthalpy change for the solid-solid  phase transition.  PbO (yellow) → PbO (red)
$$\mathrm{There}\:\mathrm{are}\:\mathrm{two}\:\mathrm{crystalline}\:\mathrm{forms}\:\mathrm{of}\:\mathrm{PbO}\:; \\ $$$$\mathrm{one}\:\mathrm{is}\:\mathrm{yellow}\:\mathrm{and}\:\mathrm{the}\:\mathrm{other}\:\mathrm{is}\:\mathrm{red}.\:\mathrm{The} \\ $$$$\mathrm{standard}\:\mathrm{enthalpies}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of} \\ $$$$\mathrm{these}\:\mathrm{two}\:\mathrm{forms}\:\mathrm{are}\:−\mathrm{217}.\mathrm{3}\:\mathrm{and}\:−\mathrm{219} \\ $$$$\mathrm{kJ}\:\mathrm{per}\:\mathrm{mole}\:\mathrm{respectively}.\:\mathrm{Calculate}\:\mathrm{the} \\ $$$$\mathrm{enthalpy}\:\mathrm{change}\:\mathrm{for}\:\mathrm{the}\:\mathrm{solid}-\mathrm{solid} \\ $$$$\mathrm{phase}\:\mathrm{transition}. \\ $$$$\mathrm{PbO}\:\left(\mathrm{yellow}\right)\:\rightarrow\:\mathrm{PbO}\:\left(\mathrm{red}\right) \\ $$

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