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Question Number 33557 by JohnQuinceyStClair last updated on 19/Apr/18

{T h i s}^{} {i s}^{} a^{} f o r m u l a .

{w o r k i n g}^{} {o u t}^{} {t h e}^{} {a r e a}^{} {b e t w e e n}^{} t w o

{T o r o i d a l}^{} c o i l s .

{B o t h}^{} {w i t h}^{} a^{} {m a g n e t i c}^{} {s p r i n g}^{} c o n s t a n t .

r = r a d i u s = 1

a = a r e a = 2

k^{z} = \frac{1}{(r + a)} - \frac{1}{r^{2}} = - a \frac{(2 \cdot r + a)}{[{(r + a)}^{2} \cdot r^{2}]}

r a t i o = ?

{w h a t}^{} {i s}^{} {t h e}^{} r a t i o ?