Question Number 25533 by pieroo last updated on 11/Dec/17
$${Three}\:{sets}\:{of}\:{beans}\:{l},\:{m},\:{and}\:{n}\:{are}\:{sold}\:{for}\mathrm{5} \\ $$$${for}\:\$\mathrm{5}.\mathrm{00},\:\$\mathrm{15}.\mathrm{00}\:{and}\:\$\mathrm{17}.\mathrm{50}\:{respectively} \\ $$$${per}\:{kg}.\:{If}\:{they}\:{are}\:{mixed}\:{in}\:{the}\:{ratio}\:{of} \\ $$$$\mathrm{1}:\mathrm{3}:\mathrm{2},\:{what}\:{is}\:{the}\:{cost}\:{per}\:{kg}\:{of}\:{the}\:{mixture}?× \\ $$
Answered by mrW1 last updated on 11/Dec/17
$$\frac{\mathrm{1}}{\mathrm{6}}×\mathrm{5}+\frac{\mathrm{3}}{\mathrm{6}}×\mathrm{15}+\frac{\mathrm{2}}{\mathrm{6}}×\mathrm{17}.\mathrm{5}=\frac{\mathrm{85}}{\mathrm{6}}=\mathrm{14}.\mathrm{17}\:\$/{kg} \\ $$
Commented by pieroo last updated on 11/Dec/17
$$\mathrm{thanks}\:\mathrm{pal} \\ $$