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Question Number 102638 by bemath last updated on 10/Jul/20

t o M r W

i f o r g o t t h e f o r m u l a t o f i n d

t h e a r e a o f a t r i a n g l e b y

u s i n g t h e t h r e e h e i g h t l i n e

Commented by Ar Brandon last updated on 10/Jul/20

P e r m i t m e t o i n t e r v a i n

Maybe you should just search triangle .

It is possible with the recent update .

Commented by bemath last updated on 10/Jul/20

h o w s i r ?

Commented by mr W last updated on 10/Jul/20

d o y o u m e a n Q 97236 ?

Commented by bemath last updated on 10/Jul/20

y e s s i r . t h a n k y o u

Commented by Ar Brandon last updated on 10/Jul/20

I meant in "search question"��

Commented by bemath last updated on 10/Jul/20

��

Answered by bramlex last updated on 10/Jul/20

area = \frac{1}{\sqrt{(\frac{1}{h_{1}} + \frac{1}{h_{2}} + \frac{1}{h_{3}}) (- \frac{1}{h_{1}} + \frac{1}{h_{2}} + \frac{1}{h_{3}}) (\frac{1}{h_{1}} - \frac{1}{h_{2}} + \frac{1}{h_{3}}) (\frac{1}{h_{1}} + \frac{1}{h_{2}} - \frac{1}{h_{3}})}}

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