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tow-type-creams-are-in-a-box-that-one-type-of-these-have-25gr-mass-and-another-ones-have-37gr-mass-if-the-total-mass-of-those-is-870gr-then-find-the-number-of-each-type-of-creams-




Question Number 192046 by sciencestudentW last updated on 06/May/23
tow type creams are in a box that one   type of these have 25gr mass and another  ones have 37gr mass, if the total mass  of those is 870gr then find the number  of each type of creams.
$${tow}\:{type}\:{creams}\:{are}\:{in}\:{a}\:{box}\:{that}\:{one}\: \\ $$$${type}\:{of}\:{these}\:{have}\:\mathrm{25}{gr}\:{mass}\:{and}\:{another} \\ $$$${ones}\:{have}\:\mathrm{37}{gr}\:{mass},\:{if}\:{the}\:{total}\:{mass} \\ $$$${of}\:{those}\:{is}\:\mathrm{870}{gr}\:{then}\:{find}\:{the}\:{number} \\ $$$${of}\:{each}\:{type}\:{of}\:{creams}. \\ $$
Answered by Skabetix last updated on 06/May/23
37×10+20×25=870  →20 of type 1 and 10 of type 2
$$\mathrm{37}×\mathrm{10}+\mathrm{20}×\mathrm{25}=\mathrm{870} \\ $$$$\rightarrow\mathrm{20}\:{of}\:{type}\:\mathrm{1}\:{and}\:\mathrm{10}\:{of}\:{type}\:\mathrm{2} \\ $$
Commented by sciencestudentW last updated on 07/May/23
if the total number of creams are 30 in  a box then how we can solve by equation?
$${if}\:{the}\:{total}\:{number}\:{of}\:{creams}\:{are}\:\mathrm{30}\:{in} \\ $$$${a}\:{box}\:{then}\:{how}\:{we}\:{can}\:{solve}\:{by}\:{equation}? \\ $$
Answered by Skabetix last updated on 07/May/23
We have 25x+37y=870 and x+y=30  ⇔x=30−y  ⇔25(30−y)+37y=870  ⇔750−25y+37y=870  ⇔12y=870−750=120  ⇔y=((120)/(12))=10    x+y=30  ⇔x+10=30  x=30−10=20  → 20 of type 1 and 10 of type 2
$${We}\:{have}\:\mathrm{25}{x}+\mathrm{37}{y}=\mathrm{870}\:{and}\:{x}+{y}=\mathrm{30} \\ $$$$\Leftrightarrow{x}=\mathrm{30}−{y} \\ $$$$\Leftrightarrow\mathrm{25}\left(\mathrm{30}−{y}\right)+\mathrm{37}{y}=\mathrm{870} \\ $$$$\Leftrightarrow\mathrm{750}−\mathrm{25}{y}+\mathrm{37}{y}=\mathrm{870} \\ $$$$\Leftrightarrow\mathrm{12}{y}=\mathrm{870}−\mathrm{750}=\mathrm{120} \\ $$$$\Leftrightarrow{y}=\frac{\mathrm{120}}{\mathrm{12}}=\mathrm{10} \\ $$$$ \\ $$$$\mathrm{x}+\mathrm{y}=\mathrm{30} \\ $$$$\Leftrightarrow{x}+\mathrm{10}=\mathrm{30} \\ $$$${x}=\mathrm{30}−\mathrm{10}=\mathrm{20} \\ $$$$\rightarrow\:\mathrm{20}\:{of}\:{type}\:\mathrm{1}\:{and}\:\mathrm{10}\:{of}\:{type}\:\mathrm{2} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$
Commented by sciencestudentW last updated on 07/May/23
thanks a lot
$${thanks}\:{a}\:{lot} \\ $$

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