transform-tanp-tanq-then-find-the-value-of-k-1-n-1-cos-k-cos-k-1-R- Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 28608 by abdo imad last updated on 27/Jan/18 transformtanp−tanqthenfindthevalueof∑k=1n1cos(kθ)cos((k+1)θ.θ∈R. Answered by Tinkutara last updated on 28/Jan/18 1coskθcos(k+1)θ=cos[(k+1)θ−kθ]coskθcos(k+1)θcosθ=cos(k+1)θcosθ+sin(k+1)θsinθcoskθcos(k+1)θcosθ=1+tan(k+1)θtanθcosθ=tan(k+1)θ−tanθsinθTelescopingitbecomes∑nk=1tan(k+1)θ−tanθsinθ=tan(n+1)θ−tanθsinθ Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: simplify-k-0-n-1-3-k-sin-3-3-k-1-Next Next post: calculate-cotanx-2cotan-2x-then-simlify-k-0-n-1-2-k-tan-2-k- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.