Triangle-ABC-has-AB-2-AC-Let-D-and-E-be-on-AB-and-BC-respectively-such-that-BAE-ACD-Let-F-be-the-intersections-of-segments-AE-and-CD-and-suppose-that-CFE-is-equilateral-What-is-ACB-

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Question Number 111279 by Aina Samuel Temidayo last updated on 03/Sep/20

$$\mathrm{Triangle}\mathrm{ABC}\mathrm{has}\mathrm{AB}=2\cdot \mathrm{AC}.\mathrm{Let}$$$$\mathrm{D}\mathrm{and}\mathrm{E}\mathrm{be}\mathrm{on}\mathrm{AB}\mathrm{and}\mathrm{BC}$$$$\mathrm{respectively}\mathrm{such}\mathrm{that}\mathrm{\angle }\mathrm{BAE}$$$$=\mathrm{\angle }\mathrm{ACD}.\mathrm{Let}\mathrm{F}\mathrm{be}\mathrm{the}\mathrm{intersections}\mathrm{of}$$$$\mathrm{segments}\mathrm{AE}\mathrm{and}\mathrm{CD},\mathrm{and}\mathrm{suppose}$$$$\mathrm{that}△\mathrm{CFE}\mathrm{is}\mathrm{equilateral}.\mathrm{What}\mathrm{is}$$$$\mathrm{\angle }\mathrm{ACB}?$$

Answered by nimnim last updated on 03/Sep/20

$$90°$$

Commented by Aina Samuel Temidayo last updated on 03/Sep/20

$$\mathrm{Solution}\mathrm{please}?$$

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