Triangle-ABC-has-AB-2-AC-Let-D-and-E-be-on-AB-and-BC-respectively-such-that-BAE-ACD-Let-F-be-the-intersections-of-segments-AE-and-CD-and-suppose-that-CFE-is-equilateral-What-is-ACB-

Question Number 111279 by Aina Samuel Temidayo last updated on 03/Sep/20

$$\mathrm{Triangle}\:\mathrm{ABC}\:\mathrm{has}\:\mathrm{AB}=\mathrm{2}\centerdot\mathrm{AC}.\:\mathrm{Let} \\ $$$$\mathrm{D}\:\mathrm{and}\:\mathrm{E}\:\mathrm{be}\:\mathrm{on}\:\mathrm{AB}\:\mathrm{and}\:\mathrm{BC} \\ $$$$\mathrm{respectively}\:\mathrm{such}\:\mathrm{that}\:\angle\mathrm{BAE} \\ $$$$=\angle\mathrm{ACD}.\:\mathrm{Let}\:\mathrm{F}\:\mathrm{be}\:\mathrm{the}\:\mathrm{intersections}\:\mathrm{of} \\ $$$$\mathrm{segments}\:\mathrm{AE}\:\mathrm{and}\:\mathrm{CD},\:\mathrm{and}\:\mathrm{suppose} \\ $$$$\mathrm{that}\:\bigtriangleup\mathrm{CFE}\:\mathrm{is}\:\mathrm{equilateral}.\:\mathrm{What}\:\mathrm{is} \\ $$$$\angle\mathrm{ACB}? \\ $$

Answered by nimnim last updated on 03/Sep/20

$$\mathrm{90}° \\ $$

Commented by Aina Samuel Temidayo last updated on 03/Sep/20

$$\mathrm{Solution}\:\mathrm{please}? \\ $$

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