Triangle-ABC-have-sin2A-sin2B-sin2C-3-cosA-cosB-cosC-gt-Prove-that-ABC-is-equilateral-triangle-

Question Number 189012 by TUN last updated on 10/Mar/23

T r i a n g l e A B C h a v e :

s i n 2 A + s i n 2 B + s i n 2 C = \sqrt{3} (c o s A + c o s B + c o s C)

=> P r o v e t h a t A B C i s e q u i l a t e r a l t r i a n g l e