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Question Number 120621 by TANMAY PANACEA last updated on 01/Nov/20
Trigonometry  selective questions
Trigonometryselectivequestions
Commented by TANMAY PANACEA last updated on 01/Nov/20
Commented by TANMAY PANACEA last updated on 01/Nov/20
Commented by TANMAY PANACEA last updated on 01/Nov/20
Commented by Dwaipayan Shikari last updated on 01/Nov/20
S=(1+tan1°)(1+tan2°)...  (1+tan1°)=1+((1−tan44°)/(1+tan44°))=(2/(1+tan44°))  (1+tan2°)=(2/(1+tan43°))  S^2 =4.(2.2.2...44)  S^2 =2^(46)   S=2^(23)   n=23
S=(1+tan1°)(1+tan2°)(1+tan1°)=1+1tan44°1+tan44°=21+tan44°(1+tan2°)=21+tan43°S2=4.(2.2.244)S2=246S=223n=23
Commented by TANMAY PANACEA last updated on 01/Nov/20
(1+tan1)  (tan45+tan1)=(((sin45cos1+cos45sin1)/(cos45cos1)))  (((sin46)/(cos45cos1)))  so  p=((sin46)/(cos45cos1))×((sin47)/(cos45cos2))×((sin48)/(cos45cos3))×..×((sin89)/(cos45cos44))×((sin90)/(cos45cos45))  =now look  sin46=cos44..  sin47=cos43  so cancel out  p=((1/(cos45)))^(44) ×((1/(cos45)))^2 =((√2) )^(46) =2^(23)
(1+tan1)(tan45+tan1)=(sin45cos1+cos45sin1cos45cos1)(sin46cos45cos1)sop=sin46cos45cos1×sin47cos45cos2×sin48cos45cos3×..×sin89cos45cos44×sin90cos45cos45=nowlooksin46=cos44..sin47=cos43socanceloutp=(1cos45)44×(1cos45)2=(2)46=223
Commented by TANMAY PANACEA last updated on 01/Nov/20
thank you Dawiayan
thankyouDawiayan
Commented by bobhans last updated on 01/Nov/20
Commented by TANMAY PANACEA last updated on 02/Nov/20
thank you sir
thankyousir

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