Trigonometry-selective-questions-

Question Number 120621 by TANMAY PANACEA last updated on 01/Nov/20

T r i g o n o m e t r y

s e l e c t i v e q u e s t i o n s

Commented by TANMAY PANACEA last updated on 01/Nov/20

Commented by TANMAY PANACEA last updated on 01/Nov/20

Commented by TANMAY PANACEA last updated on 01/Nov/20

Commented by Dwaipayan Shikari last updated on 01/Nov/20

S = (1 + t a n 1 °) (1 + t a n 2 °) \dots

(1 + t a n 1 °) = 1 + \frac{1 - t a n 44 °}{1 + t a n 44 °} = \frac{2}{1 + t a n 44 °}

(1 + t a n 2 °) = \frac{2}{1 + t a n 43 °}

S^{2} = 4 . (2.2.2 \dots 44)

S^{2} = 2^{46}

S = 2^{23}

n = 23

Commented by TANMAY PANACEA last updated on 01/Nov/20

(1 + t a n 1)

(t a n 45 + t a n 1) = (\frac{s i n 45 c o s 1 + c o s 45 s i n 1}{c o s 45 c o s 1})

(\frac{s i n 46}{c o s 45 c o s 1})

s o

p = \frac{s i n 46}{c o s 45 c o s 1} \times \frac{s i n 47}{c o s 45 c o s 2} \times \frac{s i n 48}{c o s 45 c o s 3} \times . . \times \frac{s i n 89}{c o s 45 c o s 44} \times \frac{s i n 90}{c o s 45 c o s 45}

= n o w l o o k

s i n 46 = c o s 44 . .

s i n 47 = c o s 43 s o c a n c e l o u t

p = {(\frac{1}{c o s 45})}^{44} \times {(\frac{1}{c o s 45})}^{2} = {(\sqrt{2})}^{46} = 2^{23}

Commented by TANMAY PANACEA last updated on 01/Nov/20

t h a n k y o u D a w i a y a n

Commented by bobhans last updated on 01/Nov/20

Commented by TANMAY PANACEA last updated on 02/Nov/20

t h a n k y o u s i r