Trigonometry-solve-Equation-sin-x-2-2sin-x-3-0- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 159325 by mnjuly1970 last updated on 15/Nov/21 You can't use 'macro parameter character #' in math modeYou can't use 'macro parameter character #' in math modeYou can't use 'macro parameter character #' in math modesolve(Equation)sin(x2)−2sin(x3)=0 Commented by Ar Brandon last updated on 15/Nov/21 x=12πn±12arctan(57+427) Answered by mr W last updated on 15/Nov/21 sin(3x6)−2sin(2x6)=0lett=x6sin(3t)−2sin(2t)=0sint(3−4sin2t)−4sintcost=0sint(4cos2t−4cost−1)=0sint=0⇒t=kπ⇒x=6kπ4cos2t−4cost−1=0cost=1±22=−2−12(+rejected)⇒t=(2k+1)π±cos−12−12⇒x=6(2k+1)π±6cos−12−12 Commented by mnjuly1970 last updated on 16/Nov/21 verynicesirW Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: let-give-p-1-2-1-1-and-D-3-6-2-2-calculate-A-p-D-p-1-Next Next post: how-to-think-from-1-2-3-n-n-n-1-2-1-2-2-2-3-2-n-2-n-n-1-2n-1-6-1-3-2-3-3-3-n-3-n-n-1-2-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.