Question Number 18965 by Tinkutara last updated on 02/Aug/17
$$\mathrm{Two}\:\mathrm{blocks}\:\mathrm{of}\:\mathrm{masses}\:{M}\:\mathrm{and}\:\mathrm{2}{M}\:\mathrm{are} \\ $$$$\mathrm{connected}\:\mathrm{to}\:\mathrm{each}\:\mathrm{other}\:\mathrm{through}\:\mathrm{a}\:\mathrm{light} \\ $$$$\mathrm{spring}\:\mathrm{as}\:\mathrm{shown}\:\mathrm{in}\:\mathrm{figure}.\:\mathrm{If}\:\mathrm{we}\:\mathrm{push}\:\mathrm{the} \\ $$$$\mathrm{mass}\:{M}\:\mathrm{with}\:\mathrm{a}\:\mathrm{force}\:{F}\:\mathrm{which}\:\mathrm{cause} \\ $$$$\mathrm{acceleration}\:\mathrm{a}\:\mathrm{in}\:\mathrm{mass}\:{M},\:\mathrm{what}\:\mathrm{will}\:\mathrm{the} \\ $$$$\mathrm{acceleration}\:\mathrm{in}\:\mathrm{2}{M}? \\ $$
Commented by Tinkutara last updated on 02/Aug/17
Commented by Tinkutara last updated on 03/Aug/17
$$\mathrm{But}\:\mathrm{in}\:\mathrm{options}\:\mathrm{it}\:\mathrm{is}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:{F},{M}\mathrm{and}\:{a}. \\ $$
Commented by ajfour last updated on 02/Aug/17
$$\mathrm{initially}\:\mathrm{zero}\:. \\ $$
Answered by ajfour last updated on 03/Aug/17
$$\mathrm{F}−\mathrm{kx}=\mathrm{Ma} \\ $$$$\mathrm{kx}=\mathrm{2MA} \\ $$$$\Rightarrow\:\mathrm{A}=\frac{\mathrm{kx}}{\mathrm{2M}}=\frac{\mathrm{F}−\mathrm{Ma}}{\mathrm{2M}} \\ $$$$\:\:\mathrm{A}=\frac{\mathrm{F}}{\mathrm{2M}}−\frac{\mathrm{a}}{\mathrm{2}}\:.\:\:\: \\ $$$$\left(\mathrm{A}\:\mathrm{being}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{2M}\right).\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$
Commented by Tinkutara last updated on 03/Aug/17
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$