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Two-consecutive-integers-between-which-a-root-of-the-equation-1-x-3-x-16-0-2-x-2-3x-2-0-lies-are-




Question Number 64347 by Rio Michael last updated on 16/Jul/19
Two consecutive integers between which a root of the equation   1)x^3 +x−16=0   2) x^2 −3x+2=0  lies are;
$${Two}\:{consecutive}\:{integers}\:{between}\:{which}\:{a}\:{root}\:{of}\:{the}\:{equation} \\ $$$$\left.\:\mathrm{1}\right){x}^{\mathrm{3}} +{x}−\mathrm{16}=\mathrm{0}\: \\ $$$$\left.\mathrm{2}\right)\:{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2}=\mathrm{0} \\ $$$${lies}\:{are}; \\ $$

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