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Two-different-prime-numbers-between-4-and-18-are-chosen-When-their-sum-is-subtracted-from-their-product-then-a-number-x-is-obtained-which-is-a-multiple-of-17-Find-the-sum-of-digits-of-number-x-




Question Number 19631 by Tinkutara last updated on 13/Aug/17
Two different prime numbers between  4 and 18 are chosen. When their sum is  subtracted from their product then a  number x is obtained which is a  multiple of 17. Find the sum of digits of  number x.
Twodifferentprimenumbersbetween4and18arechosen.Whentheirsumissubtractedfromtheirproductthenanumberxisobtainedwhichisamultipleof17.Findthesumofdigitsofnumberx.
Answered by ajfour last updated on 13/Aug/17
let p and q .       pq−(p+q)=17n  p, q can be  among  5,7,11,13,17  if p=17, q=13  15^2 −4−30=191≠17n  if p=17, q=11  196−9−28=159≠17n  if p=17, q=7  144−25−24=95≠17n  if p=17, q=5  85−22=63≠17n  ........................................  if p=13, q=11  143−24=119=17×7  if p=13, q=7  91−20=71≠17n  if p=13, q=5  65−18=47≠17n  if p=11, q=7  77−18=59≠17n  if p=11, q=5  55−16=39≠17n  if p=7, q=5  35−12=23≠17n  Hence x=17×7=119  Sum of its digits=11 .
letpandq.pq(p+q)=17np,qcanbeamong5,7,11,13,17ifp=17,q=13152430=19117nifp=17,q=11196928=15917nifp=17,q=71442524=9517nifp=17,q=58522=6317n.ifp=13,q=1114324=119=17×7ifp=13,q=79120=7117nifp=13,q=56518=4717nifp=11,q=77718=5917nifp=11,q=55516=3917nifp=7,q=53512=2317nHencex=17×7=119Sumofitsdigits=11.
Commented by Tinkutara last updated on 13/Aug/17
So totally hit and trial method is  applicable?
Sototallyhitandtrialmethodisapplicable?
Commented by ajfour last updated on 13/Aug/17
dint know a decent way out..
dintknowadecentwayout..

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