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Question Number 60576 by hovea cw last updated on 22/May/19
two faire dices are tossed together  find the probability that the   total score is atmost 4
$$\mathrm{two}\:\mathrm{faire}\:\mathrm{dices}\:\mathrm{are}\:\mathrm{tossed}\:\mathrm{together} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{the}\: \\ $$$$\mathrm{total}\:\mathrm{score}\:\mathrm{is}\:\mathrm{atmost}\:\mathrm{4} \\ $$$$ \\ $$
Commented by hovea cw last updated on 22/May/19
help plzx
$$\mathrm{help}\:\mathrm{plzx} \\ $$
Commented by mr W last updated on 22/May/19
1+1  1+2  2+2  1+3  sum=2×4=8  total 6×6=36  ⇒p=(8/(36))=(2/9)
$$\mathrm{1}+\mathrm{1} \\ $$$$\mathrm{1}+\mathrm{2} \\ $$$$\mathrm{2}+\mathrm{2} \\ $$$$\mathrm{1}+\mathrm{3} \\ $$$${sum}=\mathrm{2}×\mathrm{4}=\mathrm{8} \\ $$$${total}\:\mathrm{6}×\mathrm{6}=\mathrm{36} \\ $$$$\Rightarrow{p}=\frac{\mathrm{8}}{\mathrm{36}}=\frac{\mathrm{2}}{\mathrm{9}} \\ $$
Commented by hovea cw last updated on 22/May/19
ttanks sir
$$\mathrm{ttanks}\:\mathrm{sir}\: \\ $$
Commented by MJS last updated on 22/May/19
sorry but this is not true
$$\mathrm{sorry}\:\mathrm{but}\:\mathrm{this}\:\mathrm{is}\:\mathrm{not}\:\mathrm{true} \\ $$
Answered by MJS last updated on 22/May/19
11  12, 21  13, 31  22  =6 possible combinations  14 15 16  23 24 25 26  32 33 34 35 36  41 42 43 44 45 46  51 52 53 54 55 56  61 62 63 64 65 66  =30  ⇒ (6/(36))=(1/6)
$$\mathrm{11} \\ $$$$\mathrm{12},\:\mathrm{21} \\ $$$$\mathrm{13},\:\mathrm{31} \\ $$$$\mathrm{22} \\ $$$$=\mathrm{6}\:\mathrm{possible}\:\mathrm{combinations} \\ $$$$\mathrm{14}\:\mathrm{15}\:\mathrm{16} \\ $$$$\mathrm{23}\:\mathrm{24}\:\mathrm{25}\:\mathrm{26} \\ $$$$\mathrm{32}\:\mathrm{33}\:\mathrm{34}\:\mathrm{35}\:\mathrm{36} \\ $$$$\mathrm{41}\:\mathrm{42}\:\mathrm{43}\:\mathrm{44}\:\mathrm{45}\:\mathrm{46} \\ $$$$\mathrm{51}\:\mathrm{52}\:\mathrm{53}\:\mathrm{54}\:\mathrm{55}\:\mathrm{56} \\ $$$$\mathrm{61}\:\mathrm{62}\:\mathrm{63}\:\mathrm{64}\:\mathrm{65}\:\mathrm{66} \\ $$$$=\mathrm{30} \\ $$$$\Rightarrow\:\frac{\mathrm{6}}{\mathrm{36}}=\frac{\mathrm{1}}{\mathrm{6}} \\ $$

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