Question Number 17715 by tawa tawa last updated on 09/Jul/17
$$\mathrm{Two}\:\mathrm{forces}\:\mathrm{5N}\:\mathrm{and}\:\mathrm{6N}\:\mathrm{acting}\:\mathrm{at}\:\mathrm{a}\:\mathrm{point}\:\mathrm{are}\:\mathrm{inclined}\:\mathrm{at}\:\mathrm{60}°\:\mathrm{to}\:\mathrm{each}\:\mathrm{other}.\: \\ $$$$\mathrm{Calculate}\:\mathrm{their}\:\mathrm{resultant}.\: \\ $$
Answered by Tinkutara last updated on 09/Jul/17
$$\sqrt{\mathrm{5}^{\mathrm{2}} \:+\:\mathrm{6}^{\mathrm{2}} \:+\:\mathrm{2}\left(\mathrm{5}\right)\left(\mathrm{6}\right)\frac{\mathrm{1}}{\mathrm{2}}}\:=\:\sqrt{\mathrm{25}\:+\:\mathrm{36}\:+\:\mathrm{30}} \\ $$$$=\:\sqrt{\mathrm{91}} \\ $$
Commented by tawa tawa last updated on 09/Jul/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$