Two-large-parallel-metal-plates-carrying-opposite-charges-are-seperated-by-a-distance-of-0-2m-and-the-potential-difference-between-them-is-0-5KV-a-Calculate-the-magnitude-of-the-uniform-electric-fie

Question Number 40818 by Necxx last updated on 27/Jul/18

T w o l a r g e p a r a l l e l m e t a l p l a t e s c a r r y i n g

o p p o s i t e c h a r g e s a r e s e p e r a t e d b y a

d i s t a n c e o f 0.2 m, a n d t h e p o t e n t i a l

d i f f e r e n c e b e t w e e n t h e m i s 0.5 K V .

(a) C a l c u l a t e t h e m a g n i t u d e o f t h e

u n i f o r m e l e c t r i c f i e l d b e t w e e n t h e m .

(b) A l s o c a l c u l a t e t h e w o r k d o n e b y

t h i s f i e l d o n a c h a r g e o f 4.0 \times 10^{- 9} C

w h e n i t m o v e s f r o m t h e p l a t e o f

h i g h e r p o t e n t i a l t o t h a t o f l o w e r

p o t e n t i a l .

Answered by tanmay.chaudhury50@gmail.com last updated on 28/Jul/18

E = \frac{V}{d} = \frac{0.5 \times 10^{3}}{0.2} = 2.5 \times 10^{3}

W = q V = 4.0 \times 10^{- 9} \times 0.5 \times 10^{3} = 2.0 \times 10^{- 6}