Menu Close

Two-particles-A-and-B-start-from-the-same-position-along-the-circular-path-of-radius-0-5-m-with-a-speed-v-A-1-ms-1-and-v-B-1-2-ms-1-in-opposite-direction-Determine-the-time-before-they-




Question Number 20786 by Tinkutara last updated on 02/Sep/17
Two particles A and B start from the  same position along the circular path of  radius 0.5 m with a speed v_A  = 1 ms^(−1)   and v_B  = 1.2 ms^(−1)  in opposite direction.  Determine the time before they collide.
TwoparticlesAandBstartfromthesamepositionalongthecircularpathofradius0.5mwithaspeedvA=1ms1andvB=1.2ms1inoppositedirection.Determinethetimebeforetheycollide.
Answered by dioph last updated on 03/Sep/17
θ_A  = ω_A t = ((v_A t)/r) = ((1×t)/(0.5)) = 2t  θ_B  = 2π − ω_B t = 2π − ((v_B t)/r) = 2π −((1.2×t)/(0.5)) = 2π−2.4t  θ_A  = θ_B  ⇔ 2t = 2π−2.4t ⇔  ⇔ 4.4t = 2π ⇔ t = ((2π)/(4.4)) s
θA=ωAt=vAtr=1×t0.5=2tθB=2πωBt=2πvBtr=2π1.2×t0.5=2π2.4tθA=θB2t=2π2.4t4.4t=2πt=2π4.4s
Commented by Tinkutara last updated on 03/Sep/17
Thank you very much Sir!
ThankyouverymuchSir!
Answered by mrW1 last updated on 03/Sep/17
t=((2πr)/(v_A +v_B ))=((2π×0.5)/(1+1.2))=(π/(2.2))=1.43 s
t=2πrvA+vB=2π×0.51+1.2=π2.2=1.43s
Commented by Tinkutara last updated on 03/Sep/17
Thank you very much Sir!
ThankyouverymuchSir!

Leave a Reply

Your email address will not be published. Required fields are marked *