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Question Number 16497 by Tinkutara last updated on 23/Jun/17

Two particles are revolving on two

coplanar circles with constant angular

velocities ω_{1} and ω_{2} respectively . Their

time periods are T_{1} and T_{2} then prove

that the time taken by second particle

to complete one revolution more than

the first particle, T, is given by

T = \frac{T_{1} T_{2}}{T_{1} - T_{2}}

Answered by ajfour last updated on 23/Jun/17

△ t = \frac{2 π}{△ ω} = \frac{2 π}{(\frac{2 π}{T_{2}} - \frac{2 π}{T_{1}})} = \frac{T_{1} T_{2}}{T_{1} - T_{2}} .

Commented by Tinkutara last updated on 23/Jun/17

Thanks Sir!