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U-ax-bx-c-dy-is-subject-to-I-mx-ny-What-happens-to-the-maximum-point-of-x-when-a-increases-Explain-your-answer-Use-Lagrange-method-




Question Number 90803 by askask last updated on 26/Apr/20
U=ax−bx^c +dy is subject to I=mx+ny.    What happens to the maximum point of x,  when a increases? Explain your answer.    (Use Lagrange method)
$${U}={ax}−{bx}^{{c}} +{dy}\:\mathrm{is}\:\mathrm{subject}\:\mathrm{to}\:\mathrm{I}={mx}+{ny}. \\ $$$$ \\ $$$$\mathrm{What}\:\mathrm{happens}\:\mathrm{to}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{point}\:\mathrm{of}\:\boldsymbol{{x}}, \\ $$$${when}\:\boldsymbol{{a}}\:\mathrm{increases}?\:\mathrm{Explain}\:\mathrm{your}\:\mathrm{answer}. \\ $$$$ \\ $$$$\left(\mathrm{Use}\:\mathrm{Lagrange}\:\mathrm{method}\right) \\ $$

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