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Use-polar-coordinate-to-find-lim-x-y-0-0-y-2-x-2-y-2-




Question Number 187611 by otchereabdullai last updated on 19/Feb/23
 Use polar coordinate to find  lim(x,y)→(0,0) (y^2 /(x^2 +y^2 ))
Usepolarcoordinatetofindlim(x,y)(0,0)y2x2+y2
Answered by mahdipoor last updated on 19/Feb/23
not exist   get y=0 and x→0 ⇒ lim=(0/(x^2 +0))=0  get y→0 and x=0 ⇒ lim=(y^2 /(0+y^2 ))=1  get (y=x)→0 ⇒ lim=(x^2 /(x^2 +x^2 ))=(1/2)  ...
notexistgety=0andx0lim=0x2+0=0gety0andx=0lim=y20+y2=1get(y=x)0lim=x2x2+x2=12
Answered by a.lgnaoui last updated on 19/Feb/23
I think that a rule of l hopital  can get a solutiin  f(x)=x^2 +y^2      g(x)=y^2   lim_(x→a) ((f/g)) =lim_(x→a) (((f′)/g^′ ))  with ((d(x^2 +y^2 ))/(d(x,y)))=?
Ithinkthataruleoflhopitalcangetasolutiinf(x)=x2+y2g(x)=y2limxa(fg)=limxa(fg)withd(x2+y2)d(x,y)=?

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