use-the-appropite-set-law-to-show-that-A-B-B-A-A-B-A-B-

Question Number 22162 by j.masanja06@gmail.com last updated on 12/Oct/17

u s e t h e a p p r o p i t e s e t l a w t o s h o w

t h a t

(A - B) \cup (B - A) = (A \cup B) - (A \cap B)

Answered by $@ty@m last updated on 12/Oct/17

(A \cup B) - (A \cap B) \Leftrightarrow (A \cup B) \cap {(A \cap B)}^{^{'}}

\Leftrightarrow (A \cup B) \cap (A^{^{'}} \cup B^{^{'}})

\Leftrightarrow {(A \cup B) \cap A^{^{'}}} \cup {(A \cup B) \cap B^{^{'}}}

\Leftrightarrow {(A \cap A^{^{'}}) \cup (B \cap A^{'})} \cup {(A \cap B^{^{'}}) \cup (B \cap B^{'})}

\Leftrightarrow (B \cap A^{'}) \cup (A \cap B^{^{'}})

\Leftrightarrow (B - A) \cup (A - B)

Commented by Rasheed.Sindhi last updated on 13/Oct/17

N i c e!