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using-1st-principle-find-the-derivative-of-y-x-x-




Question Number 26126 by NECx last updated on 20/Dec/17
using 1st principle find the  derivative of          y=x^x
using1stprinciplefindthederivativeofy=xx
Commented by abdo imad last updated on 20/Dec/17
answer to question  ew have y= e^(xlnx)   −−> (dy/dx)  =  ((d(xln(x)))/dx)  .x^x   =  (lnx  + 1)  x^x   with the condition  x>0  .
answertoquestionewhavey=exlnx>dydx=d(xln(x))dx.xx=(lnx+1)xxwiththeconditionx>0.

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