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using-PMI-show-that-n-2-the-number-5-n-ends-with-the-digits-25-




Question Number 33462 by NECx last updated on 17/Apr/18
using PMI show that ∀ n≥2 the  number 5^n  ends with the digits 25
usingPMIshowthatn2thenumber5nendswiththedigits25
Answered by MJS last updated on 17/Apr/18
base:  n=2  5^2 =25    if true for n ⇒ true for n+1  i, j ∈ N  5^n =100i+25 ⇒ 5^(n+1) =100j+25  5^(n+1) =(100i+25)×5=500i+125=  =500i+100+25=100j+25 with  j=5i+1  this holds for n≥2
base:n=252=25iftrueforntrueforn+1i,jN5n=100i+255n+1=100j+255n+1=(100i+25)×5=500i+125==500i+100+25=100j+25withj=5i+1thisholdsforn2

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