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v-pi-0-2-x-2-dx-




Question Number 91497 by kikomssn@gmail.com last updated on 01/May/20
v=π∫_0 ^2 x^2 dx
$${v}=\pi\int_{\mathrm{0}} ^{\mathrm{2}} {x}^{\mathrm{2}} {dx} \\ $$
Commented by jagoll last updated on 01/May/20
= ((πx^3 )/3) ]_0 ^2  = ((8π)/3)
$$\left.=\:\frac{\pi{x}^{\mathrm{3}} }{\mathrm{3}}\:\right]_{\mathrm{0}} ^{\mathrm{2}} \:=\:\frac{\mathrm{8}\pi}{\mathrm{3}} \\ $$

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