v-pi-1-4-1-4-x-2-2-dx-

Question Number 91500 by kikomssn@gmail.com last updated on 01/May/20

v = π \int_{1}^{4} [{(\frac{1}{4} . x^{2})}^{2} d x

Commented by john santu last updated on 01/May/20

= \frac{π}{16} \times \frac{1}{5} \times (4^{5} - 1)

= \frac{1023 π}{80}