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v-pi-1-4-1-4-x-2-2-dx-




Question Number 91500 by kikomssn@gmail.com last updated on 01/May/20
v=π∫_1 ^4 [((1/4).x^2 )^2 dx
$${v}=\pi\int_{\mathrm{1}} ^{\mathrm{4}} \left[\left(\frac{\mathrm{1}}{\mathrm{4}}.{x}^{\mathrm{2}} \right)^{\mathrm{2}} {dx}\right. \\ $$
Commented by john santu last updated on 01/May/20
= (π/(16))×(1/5)×(4^5 −1)  = ((1023π)/(80))
$$=\:\frac{\pi}{\mathrm{16}}×\frac{\mathrm{1}}{\mathrm{5}}×\left(\mathrm{4}^{\mathrm{5}} −\mathrm{1}\right) \\ $$$$=\:\frac{\mathrm{1023}\pi}{\mathrm{80}} \\ $$

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