we-give-for-t-gt-0-0-sinx-x-e-tx-dx-pi-2-arctant-use-this-result-to-find-the-value-of-0-1-e-x-sinx-x-2-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 33979 by abdo imad last updated on 28/Apr/18 wegivefort>0∫0∞sinxxe−txdx=π2−arctantusethisresulttofindthevalueof∫0∞(1−e−x)sinxx2dx. Commented by abdo mathsup 649 cc last updated on 03/May/18 weknowthat∫0∞sinxxe−txdx=π2−arctant⇒∫01(π2−arctant)dt=∫01(∫0∞sinxxe−txdx)=∫0∞(∫01e−txdt)sinxxdx(byfubini)=∫0∞([−1xe−tx]t=0t=1)sinxxdx=∫0∞1x2(1−e−x)sinxdxbut∫01(π2−arctant)dt=π2−∫01arctantdtbyparts∫01arctantdt=[tarctant]01−∫10t1+t2dt=π4−12[ln(1+t2)]01=π4−12ln(2)⇒∫0∞(1−e−x)sinxx2dx=π4+12ln(2). Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: find-a-polynome-solution-of-the-diifferencial-equation-y-y-x-12-Next Next post: 1-let-consider-f-x-cosx-pi-periodix-developp-f-at-fourier-serie-2-find-the-valueof-n-1-1-n-4n-2-1-3-find-the-value-of-n-1-1-4n-2-1-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.