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What-are-the-roots-of-the-function-f-x-log-3-x-2log-3-x-2-1-with-x-R-Mastermind-




Question Number 174495 by Mastermind last updated on 02/Aug/22
What are the roots of the function  f(x)=(log(3^x )−2log(3))∙(x^2 −1) with  x∈R?    Mastermind
Whataretherootsofthefunctionf(x)=(log(3x)2log(3))(x21)withxR?Mastermind
Commented by kaivan.ahmadi last updated on 02/Aug/22
±1 ,2
±1,2
Commented by Mastermind last updated on 02/Aug/22
your full workings sir!
yourfullworkingssir!
Answered by Rasheed.Sindhi last updated on 02/Aug/22
f(x)=(log(3^x )−2log(3))∙(x^2 −1)=0     log(3^x )−2log(3)=0 ∣ x^2 −1=0     log(3^x )=2log(3) ∣ x^2 =1     log(3^x )=log(3^2 )  ∣  x=±1     3^x =3^2       x=2
f(x)=(log(3x)2log(3))(x21)=0log(3x)2log(3)=0x21=0log(3x)=2log(3)x2=1log(3x)=log(32)x=±13x=32x=2
Commented by Mastermind last updated on 02/Aug/22
Big thanks to you, you′re too much
Bigthankstoyou,youretoomuch
Answered by Rasheed.Sindhi last updated on 19/Aug/22
AnOther way  f(x)=(log(3^x )−2log(3))∙(x^2 −1)=0  (xlog(3)−2log(3))∙(x^2 −1)=0  log(3)(x−2)(x−1)(x+1)=0  (x−2)(x−1)(x+1)=0  x−2=0 ∣ x−1=0 ∣ x+1=0  x=2 ∣ x=1 ∣ x=−1
AnOtherwayf(x)=(log(3x)2log(3))(x21)=0(xlog(3)2log(3))(x21)=0log(3)(x2)(x1)(x+1)=0(x2)(x1)(x+1)=0x2=0x1=0x+1=0x=2x=1x=1

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