Question Number 36472 by Rio Mike last updated on 02/Jun/18
$${what}\:{is}\:{the}\:{area}\:{of}\:{the}\:{sector}\:{of}\:{a}\:{circle} \\ $$$${with}\:{Radius}\:\mathrm{3}\frac{\mathrm{1}}{\mathrm{2}}{cm}\:{at}\:\mathrm{30}°\:{from}\:{the} \\ $$$${centre}\:\left({take}\:\pi=\:\frac{\mathrm{22}}{\mathrm{7}}\right). \\ $$
Answered by math1967 last updated on 02/Jun/18
$$\frac{\mathrm{30}°}{\mathrm{360}°}×\pi×\left(\frac{\mathrm{7}}{\mathrm{2}}\right)^{\mathrm{2}} {sqcm} \\ $$$$\frac{\mathrm{1}}{\mathrm{12}}×\frac{\mathrm{22}}{\mathrm{7}}×\frac{\mathrm{49}}{\mathrm{4}}=\frac{\mathrm{77}}{\mathrm{24}}{sqcm} \\ $$