What-is-the-modulus-and-the-argument-of-1-i-1-2-

Question Number 116051 by Hassen_Timol last updated on 30/Sep/20

What is the modulus and the argument

of 1 + i (1 + \sqrt{2}) ?

Answered by Dwaipayan Shikari last updated on 30/Sep/20

z = 1 + i (1 + \sqrt{2})

∣ z ∣= \sqrt{1 + 1 + 2 + 2 \sqrt{2}} = \sqrt{4 + 2 \sqrt{2}}

\arg (z) = \tan^{- 1} (\sqrt{2} + 1)