what-is-the-particular-integral-D-2-D-1-y-e-x-sin-x- Tinku Tara June 4, 2023 Differential Equation 0 Comments FacebookTweetPin Question Number 91371 by jagoll last updated on 30/Apr/20 whatistheparticularintegral(D2+D+1)y=exsinx Commented by jagoll last updated on 30/Apr/20 yp=exsinxD2+D+1yp=xexsinx2D+1=−[(2D−1)xexsinx]=−2[exsinx+xexsinx+xexcosx]+xexsinx=−2exsinx−2xexsinx−2xexcosx+xexcosx=−2exsinx−2xexsinx−xexcosx=ex(−2sinx−2xsinx−xcosx) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 1-1-pi-2-n-2-1-n-1-n-1-2-1-pi-2-n-2-1-e-n-1-n-1-A-1-lt-2-B-1-2-C-1-gt-2-Next Next post: find-the-value-of-x-and-y-x-3-5-8-y-9- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![y_p = ((e^x sin x)/(D^2 +D+1)) y_p = ((xe^x sin x)/(2D+1)) = −[ (2D−1)xe^x sin x ] = −2[e^x sin x+xe^x sin x+xe^x cos x] +xe^x sin x = −2e^x sin x−2xe^x sin x−2xe^x cos x + xe^x cos x = −2e^x sin x−2xe^x sin x−xe^x cos x = e^x (−2sin x−2xsin x−xcos x)](https://www.tinkutara.com/question/Q91391.png)