what-is-the-particular-integral-of-D-2-6D-5-y-e-5x-

Question Number 91298 by jagoll last updated on 29/Apr/20

w h a t i s t h e p a r t i c u l a r i n t e g r a l

o f (D^{2} + 6 D + 5) y = e^{- 5 x}

Commented by john santu last updated on 29/Apr/20

Answered by niroj last updated on 29/Apr/20

PI = \frac{e^{- 5 x}}{D^{2} + 6 D + 5} = \frac{x}{2 D + 6} e^{- 5 x}

= \frac{x . e^{- 5 x}}{- 10 + 6} = - \frac{{xe}^{- 5 x}}{4} / / .

Facebook Tweet Pin