What-is-the-smallest-three-digit-number-divisible-by-2-3-7-9-4-13-without-a-remainder-

Question Number 176928 by Ar Brandon last updated on 28/Sep/22

What is the smallest three digit number

divisible by \frac{2}{3}, \frac{7}{9}, \frac{4}{13} without a remainder ?

Answered by mr W last updated on 28/Sep/22

N = \frac{2}{3} a = \frac{7}{9} b = \frac{4}{13} c

a = 3 p, b = 9 q, c = 13 r

N = 2 p = 7 q = 4 r

\Rightarrow N = 28 k

f o r 3 d i g i t n u m b e r s N_{m i n} = 28 \times 4 = 112

Commented by Ar Brandon last updated on 28/Sep/22

Thanks

Commented by Tawa11 last updated on 28/Sep/22

Great sirs .

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