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Question Number 181275 by Linton last updated on 23/Nov/22
what is the sum of all  even factors of 1000?
whatisthesumofallevenfactorsof1000?
Commented by Rasheed.Sindhi last updated on 24/Nov/22
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Commented by Linton last updated on 24/Nov/22
well done
welldone
Commented by Acem last updated on 24/Nov/22
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Commented by Frix last updated on 23/Nov/22
1000=2^3 5^3   sum of even factors is  (1+5+5^2 +5^3 )(2+2^2 +2^3 )=2184
1000=2353sumofevenfactorsis(1+5+52+53)(2+22+23)=2184
Commented by Rasheed.Sindhi last updated on 23/Nov/22
Sir this is a complete solution,  more than a comment!
Sirthisisacompletesolution,morethanacomment!
Commented by Frix last updated on 23/Nov/22
I′ve been afraid others might claim it is  not a complete solution because I didn′t  explain it...
IvebeenafraidothersmightclaimitisnotacompletesolutionbecauseIdidntexplainit
Commented by Acem last updated on 23/Nov/22
@Sir Rasheed, Have a good evening bro.
@SirRasheed,Haveagoodeveningbro.
Answered by Acem last updated on 23/Nov/22
 even×odd= even   the 1000= 2^3  5^3     2^i  5^j   ∀ i : 2^i  is even , ∀j : 5^j  is odd   The request is the sum of the even factors of 1000   Sum= Σ_(i=1) ^3 2^i  Σ_(j=0) ^3 5^j  that means we have 12 numbers   Sum= 14 × 156= 2 184     It′s funny appearing the question 1  0  0  0
even×odd=eventhe1000=23532i5ji:2iiseven,j:5jisoddTherequestisthesumoftheevenfactorsof1000Sum=3i=12i3j=05jthatmeanswehave12numbersSum=14×156=2184Itsfunnyappearingthequestion1000
Commented by Rasheed.Sindhi last updated on 24/Nov/22
Is the following correct?:   Sum of even factors of 1000           =2×Sum of all factors of 500
Isthefollowingcorrect?:Sumofevenfactorsof1000=2×Sumofallfactorsof500
Commented by Linton last updated on 24/Nov/22
well done
welldone
Commented by Rasheed.Sindhi last updated on 24/Nov/22
@Acem, I also think so.
@Acem,Ialsothinkso.
Commented by Acem last updated on 24/Nov/22
I think yes, because either it factors were even   or odd the result after multiplying them by 2   will be even, right?
Ithinkyes,becauseeitheritfactorswereevenoroddtheresultaftermultiplyingthemby2willbeeven,right?

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