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Question Number 35231 by abdo.msup.com last updated on 17/May/18
what is the value of cos(1+i) and  cos(1−i)?
whatisthevalueofcos(1+i)andcos(1i)?
Commented by abdo mathsup 649 cc last updated on 17/May/18
we have the formulaes  cos(z)=ch(iz) and  sin(z)=sh(iz) ⇒cos(1+i)=ch(i(1+i))  =ch(−1+i) = ((e^(−1+i)   +e^(1−i) )/2)  =(1/2){  e^(−1) cos(1) +ie^(−1) sin(1) +e cos(1)−iesin(1)}  =(1/2){ (e +e^(−1) )cos(1) +i(e^(−1)  −e)sin(1)}  cos(1−i)=ch(i +1)= ((e^(1+i)  +e^(−1−i) )/2)  = (1/2){  e cos(1) +ie sin(1) +e^(−1) cos(1)−ie^(−1) sin(1)}  =(1/2){ (e +e^(−1) )cos(1) +i( e−e^(−1) )sin(1)}
wehavetheformulaescos(z)=ch(iz)andsin(z)=sh(iz)cos(1+i)=ch(i(1+i))=ch(1+i)=e1+i+e1i2=12{e1cos(1)+ie1sin(1)+ecos(1)iesin(1)}=12{(e+e1)cos(1)+i(e1e)sin(1)}cos(1i)=ch(i+1)=e1+i+e1i2=12{ecos(1)+iesin(1)+e1cos(1)ie1sin(1)}=12{(e+e1)cos(1)+i(ee1)sin(1)}

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