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Question Number 102606 by bemath last updated on 10/Jul/20
what is the volume of region  bounded by y =x^2 −2x and  y=x that is rotated about  y=4 ?
whatisthevolumeofregionboundedbyy=x22xandy=xthatisrotatedabouty=4?
Commented by bemath last updated on 10/Jul/20
Answered by Ar Brandon last updated on 10/Jul/20
Volume , V=π∫_0 ^3 {(x^2 −2x−4)^2 −(x−4)^2 }dx
Volume,V=π03{(x22x4)2(x4)2}dx
Answered by bobhans last updated on 10/Jul/20
vol = π∫_0 ^3 (4^2 −(x^2 −2x)^2 )−(4^2 −x^2 ) dx  = π∫_0 ^3 (x^2 −(x^2 −2x)^2  dx   = π∫_0 ^3 (x^2 +x^2 −2x)(2x)dx  =4π∫_0 ^3 x(x^2 −x)dx = 4π∫_0 ^3  (x^3 −x^2 ) dx  = 4π {(1/4)x^4 −(1/3)x^3 }_0 ^3 =4π {((81)/4)−((27)/3)}   =4π {((45)/4)} = 45π
vol=π30(42(x22x)2)(42x2)dx=π30(x2(x22x)2dx=π30(x2+x22x)(2x)dx=4π30x(x2x)dx=4π30(x3x2)dx=4π{14x413x3}03=4π{814273}=4π{454}=45π
Commented by Ar Brandon last updated on 10/Jul/20
What difference will it make if it was rather rotated about y=0 with respect to your solution ? ��
Commented by bemath last updated on 10/Jul/20
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