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Question Number 173165 by mr W last updated on 07/Jul/22

{w h a t}^{'} s t h e l a r g e s t n u m b e r y o u c a n

f o r m o n l y u s i n g t h e d i g i t s 1, 2, 3, 4 ?

Answered by pnuvu last updated on 07/Jul/22

4^{3^{(2 + 1)}}

Answered by mr W last updated on 08/Jul/22

2^{3^{41}} o r 3^{2^{41}} o r 4^{2^{31}} ?

2^{3^{41}} = 4^{\frac{3^{41}}{2}} > 3^{\frac{3^{41}}{2}} > 3^{\frac{1 . 5^{41}}{2} \times 2^{41}} > 3^{2^{41}}

2^{3^{41}} = 4^{\frac{3^{41}}{2}} > 4^{2^{31}}

s o t h e l a r g e s t n u m b e r i s 2^{3^{41}} .

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