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Question Number 192134 by mustafazaheen last updated on 09/May/23
when ((√2)+1)^7 =(√(57125))+(√(57124))  then   ((√2)−1)^7 =?
$$\mathrm{when}\:\left(\sqrt{\mathrm{2}}+\mathrm{1}\right)^{\mathrm{7}} =\sqrt{\mathrm{57125}}+\sqrt{\mathrm{57124}} \\ $$$$\mathrm{then}\:\:\:\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)^{\mathrm{7}} =? \\ $$
Answered by som(math1967) last updated on 09/May/23
  ((√2)−1)((√2)+1)=1  ((√2)−1)=(1/(((√2)+1)))  ((√2)−1)^7 =(1/(((√2)+1)^7 ))=(1/( (√(57125))+(√(57124))))   ((√2)−1)^7 =(((√(57125))−(√(57124)))/(57125−57124))                 =(√(57125))−(√(57124))
$$\:\:\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)\left(\sqrt{\mathrm{2}}+\mathrm{1}\right)=\mathrm{1} \\ $$$$\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)=\frac{\mathrm{1}}{\left(\sqrt{\mathrm{2}}+\mathrm{1}\right)} \\ $$$$\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)^{\mathrm{7}} =\frac{\mathrm{1}}{\left(\sqrt{\mathrm{2}}+\mathrm{1}\right)^{\mathrm{7}} }=\frac{\mathrm{1}}{\:\sqrt{\mathrm{57125}}+\sqrt{\mathrm{57124}}} \\ $$$$\:\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)^{\mathrm{7}} =\frac{\sqrt{\mathrm{57125}}−\sqrt{\mathrm{57124}}}{\mathrm{57125}−\mathrm{57124}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\sqrt{\mathrm{57125}}−\sqrt{\mathrm{57124}} \\ $$
Commented by mustafazaheen last updated on 09/May/23
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$$\:\cancel{\lesseqgtr} \\ $$

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