When-the-gas-is-ideal-and-process-is-isothermal-then-1-P-1-V-1-P-2-V-2-2-U-0-3-W-0-4-H-1-H-2-

Question Number 23940 by Tinkutara last updated on 10/Nov/17

When the gas is ideal and process is

isothermal, then

(1) P_{1} V_{1} = P_{2} V_{2}

(2) Δ U = 0

(3) Δ W = 0

(4) Δ H_{1} = Δ H_{2}

Commented by ajfour last updated on 10/Nov/17

d o n t k n o w a b o u t (4) b u t (1) a n d

(2) a r e c o r r e c t .

Commented by Tinkutara last updated on 10/Nov/17

N o w I g o t t h e s o l u t i o n :

Δ H = Δ U + Δ (P V)

S i n c e Δ U = 0 a n d P V i s c o n s t a n t s o

Δ H_{1} = Δ H_{2} = 0 .