why-x-2-x-

Question Number 14811 by Nayon last updated on 04/Jun/17

w h y \sqrt{x^{2}} =∣ x ∣ ?

Answered by mrW1 last updated on 04/Jun/17

i f x ⩾ 0, \sqrt{x^{2}} = x =∣ x ∣

i f x < 0, \sqrt{x^{2}} = \sqrt{{(- x)}^{2}} = (- x) =∣ x ∣

\Rightarrow \sqrt{x^{2}} =∣ x ∣ (a l w a y s v a l i d)

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