Question Number 15301 by Tinkutara last updated on 09/Jun/17

Answered by mrW1 last updated on 09/Jun/17

Commented by Tinkutara last updated on 10/Jun/17
![But answer is [nπ − (π/3) < x < nπ + (π/2)] ∪ {nπ + ((2π)/3) < x < nπ + ((3π)/2)} Your first set is correct but how to get the 2^(nd) set in union?](https://www.tinkutara.com/question/Q15394.png)
Commented by mrW1 last updated on 10/Jun/17

Commented by Tinkutara last updated on 10/Jun/17
