Question Number 112097 by bemath last updated on 06/Sep/20
$$\:\:\:\:\:\:\mid\mid{x}−\mathrm{1}\mid+\mathrm{1}\mid\:<\:{x} \\ $$
Commented by mr W last updated on 06/Sep/20
$$\mid{x}−\mathrm{1}\mid+\mathrm{1}<{x} \\ $$$$\mid{x}−\mathrm{1}\mid<{x}−\mathrm{1} \\ $$$$\Rightarrow{no}\:{solution},\:{since}\:\mid{a}\mid\geqslant{a}. \\ $$
Commented by bemath last updated on 06/Sep/20
$${santuyyy} \\ $$