Question Number 153450 by liberty last updated on 07/Sep/21
$$\begin{cases}{\left({x}+\mathrm{1}\right)^{\mathrm{2}} ={x}+{y}+\mathrm{2}}\\{\left({y}+\mathrm{1}\right)^{\mathrm{2}} ={y}+{z}+\mathrm{2}}\\{\left({z}+\mathrm{1}\right)^{\mathrm{2}} ={z}+{x}+\mathrm{2}}\end{cases} \\ $$
Answered by EDWIN88 last updated on 07/Sep/21
Commented by Tawa11 last updated on 07/Sep/21
$$\mathrm{weldone}\:\mathrm{sir} \\ $$