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x-1-2xln-x-y-2-1-4x-2-ln-x-y-1-2-4x-y-0-y-1-ln-x-the-public-answer-




Question Number 29275 by sorour87 last updated on 06/Feb/18
x(1−2xln x)y^((2)) +(1−4x^2 ln x)y^((1)) −(2+4x)y=0  y_1 =ln x  the public answer?
$${x}\left(\mathrm{1}−\mathrm{2}{x}\mathrm{ln}\:{x}\right){y}^{\left(\mathrm{2}\right)} +\left(\mathrm{1}−\mathrm{4}{x}^{\mathrm{2}} \mathrm{ln}\:{x}\right){y}^{\left(\mathrm{1}\right)} −\left(\mathrm{2}+\mathrm{4}{x}\right){y}=\mathrm{0} \\ $$$${y}_{\mathrm{1}} =\mathrm{ln}\:{x} \\ $$$${the}\:{public}\:{answer}? \\ $$

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